LB Booster - Printing array issue

LB Booster

Programming

Liberty BASIC language (Moderator: Richard Russell)

Printing array issue

« Previous Topic | Next Topic »

Pages: 1

Author

Topic: Printing array issue (Read 162 times)

flotulopex
Junior Member

member is offline

Gender:

Posts: 94

Printing array issue
« Thread started on: Sep 30^th, 2017, 12:08pm »

Hi,

I'm stuck in something obviously simple...but I can't see the mote in my eye.

Code:

Counter = 0
L1$ = "AAA"     : L1 = LEN(L1$)
L2$ = "BBBBB"   : L2 = LEN(L2$)
L3$ = "CCCCCCC" : L3 = LEN(L3$)
FOR Counter = 1 TO 3
    PRINT Counter, L(Counter)
NEXT Counter

How do I make L(Counter) show up correctly in the list instead of "0"?

Logged

Roger

Rod
Full Member

member is offline

Gender:

Posts: 110

Re: Printing array issue
« Reply #1 on: Sep 30^th, 2017, 2:53pm »

Code:

Counter = 0 '? Counter is set to 1 when you enter the for next loop
dim L(3) 'create the array you intend to use
'store the length to this array, not L1,L2,L3
L1$ = "AAA"     : L(1) = LEN(L1$)
L2$ = "BBBBB"   : L(2) = LEN(L2$)
L3$ = "CCCCCCC" : L(3) = LEN(L3$)
FOR Counter = 1 TO 3
    PRINT Counter, L(Counter)
NEXT Counter

Logged

Richard Russell
Administrator

member is offline

Posts: 1348

Re: Printing array issue
« Reply #2 on: Sep 30^th, 2017, 3:10pm »

on Sep 30^th, 2017, 12:08pm, flotulopex wrote:

How do I make L(Counter) show up correctly in the list instead of "0"?

Another way:

Code:

Counter = 0
L1$ = "AAA"     : L1 = LEN(L1$)
L2$ = "BBBBB"   : L2 = LEN(L2$)
L3$ = "CCCCCCC" : L3 = LEN(L3$)
FOR Counter = 1 TO 3
    PRINT Counter, EVAL("L";Counter)
NEXT Counter

Fewer changes from the original than Rod's solution, but using EVAL like this isn't recommended.

Richard.

« Last Edit: Sep 30^th, 2017, 3:11pm by Richard Russell »

Logged

flotulopex
Junior Member

member is offline

Gender:

Posts: 94

Re: Printing array issue
« Reply #3 on: Oct 1^st, 2017, 08:45am »

Thanks a lot guys wink

Logged

Roger

Pages: 1


« Previous Topic \| Next Topic »